...without having to know any trigonometric identities.

take any example for the velocity of y when gravity equals 9.8 m/s, like for you earthers:

eg.

Vy = 50 m/s

50/4.9 = Range time

= height (as well as range)

= Vx

Vy/Vx arctan = angle = 75.96 degrees

we find that regardless of what gravity is, for the height and range to be equal the ratio of Vy/Vx will always be 4:1 and hence have the same angle on any planet in the known universe.

*note - if you need the

*range*to be a certain amount more than the*height*,**multiply**Vx by that amount. for example, if the range is 2.5 times more than the height, multiply Vx by 2.5.
if you need the

*height*to be a certain amount more than the*range*,**divide**the range by that amount. for example, if the height is 2.5 times more than the range, divide the range by 2.5.
## 2 comments:

I don't understand why you divide vertical velocity with half of acceleration.

@Thuy Nguyen

50m/s divided by 9.8 is the time the object takes to achieve its maximum height. so dividing by 1/2 of gravity would equal the range time.

2Vy/9.8 also works.

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