tag:blogger.com,1999:blog-4599723592993427071.post4167194485085481550..comments2023-10-07T18:30:09.785-06:00Comments on A Mighty Nut: Determining the Angle for which Height and Range would be Equaldwdeclarehttp://www.blogger.com/profile/11460146985520390155noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-4599723592993427071.post-88490147146521328842013-09-05T20:06:44.840-06:002013-09-05T20:06:44.840-06:00@Thuy Nguyen
50m/s divided by 9.8 is the time the...@Thuy Nguyen<br /><br />50m/s divided by 9.8 is the time the object takes to achieve its maximum height. so dividing by 1/2 of gravity would equal the range time.<br /><br />2Vy/9.8 also works.dwdeclarehttps://www.blogger.com/profile/14235230729194515681noreply@blogger.comtag:blogger.com,1999:blog-4599723592993427071.post-88391732450751489472013-09-05T18:13:35.504-06:002013-09-05T18:13:35.504-06:00I don't understand why you divide vertical vel...I don't understand why you divide vertical velocity with half of acceleration.Anonymoushttps://www.blogger.com/profile/16948714447213759887noreply@blogger.com