step by step walk through.

the equation:

**(49!/6!)/[(6!/n!)(43!/[6-n!])]**= probability

*note*:

**[(6!/n!)(43!/[6-n!])]**can also be written as:

**(6,n) X (43,6-n)**.

for 6 numbers, use the

**1st part**of the equation only.

**!**= factorial (the product of an integer and all the integers below it. eg. 6! = 6*5*4*3*2*1 = 720)

**n**= numbers in the lottery you have right.

*****= multiplication, or "times" as it were.

"factorialize" the numerator only as many times as the denominator number. using n = 4 as an example, we would calculate as follows: (6,4) x (43,2) = (6*5*4*3)/(4*3*2*1)

*[*

*factorialized 4 times]*x (43*42)/(2*1)

*[factorialized 2 times] = 13,545.*

n = 6 numbers

remember, for 6 numbers we only have to calculate the first part of the above equation:

(49!/6!) = (49*48*47*46*45*44)/(6*5*4*3*2*1) = 1 in 13,983,816

n = 5 numbers

we know the answer to the first part of the equation is 13,983,816, so now let's calculate the second part:

**(6,5) X (43,1)**=

(6,5) = (6*5*4*3*2)/(5*4*3*2*1) = 6

(43,1) = 43/1 = 43

6*43 = 258

13,983,816/258 = 1 in 54,200.837

n = 4 numbers

**(6,4) X (43,2)**=

(6,4) = (6*5*4*3)/(4*3*2*1) = 15

(43,2) = (43*42)/(2*1) = 903

15*903 = 13,545

13,983,816/13,545 = 1 in 1032.397

n = 3 numbers

**(6,3) X (43,3)**=

(6,3) = (6*5*4)/(3*2*1) = 20

(43,3) = (43*42*41)/(3*2*1) = 12,341

20*12,341 = 246,820

13,983,816/246,820 = 1 in 56.656

n = 2 numbers

**(6,2) X (43,4)**=

(6,2) = (6*5)/(2*1) = 15

(43,4) = (43*42*41*40)/(4*3*2*1) = 123,410

15*123,410 = 1,851,150

13,983,816/1,851,150 = 1 in 7.554

n = 1 number

**(6,1) X (43,5)**=

(6,1) = 6/1 = 6

(43,5) = (43*42*41*40*39)/(5*4*3*2*1) = 962,598

6*962,598 = 5,775,588

13,983,816/5,775,588 = 1 in 2.421

n = 0 numbers

**(6,0) x (43,6)**=

(6,0) = 0 or no "factorialization required". it will not figure in our answer.

(43,6) = (43*42*41*40*39*38)/(6*5*4*3*2*1) = 6,096,454

13,983,816/6,096,454 = 1 in 2.294

5 numbers + Bonus

*(the following is from http://icarus.mcmaster.ca/fred/Lotto/)*

The pick of six must include 5 winning numbers plus the bonus. Since 5 of the six winning numbers must be picked, this means that one of the winning numbers must be excluded. There are six possibilities for the choice of excluded number and hence there are six ways for a pick of six to win the second place prize. The probability is thus 6/13,983,816= 1 in 2,330,636

## 1 comments:

Powerball is HUGE this week, you MUST see this

This week the Powerball jackpot is HUGE...

To have more chances of winning then any player combined you need to check this video presentation by 7 time lottery winner Richard Lustig

>>>He reveals a lot of tips and secrets on how to win the Powerball in this video<<<

The jackpots for Powerball are getting higher and higher each month and it's because more people are playing the lotto and are just playing quick picks with no method.

Richard was able to win the lotto 7 different times.. and I can tell you.. his method works awesome for Powerball.

>>>Check out his brand new free video presentation<<>>Check Out His Free Video Presentation on How to Win the Powerball Here<<<

If you don’t want it then let me know and I can give it to someone else.

All the best, Ana

## Post a Comment